Question

Proficient

A cheetah travelling initially at a speed of 25 m/s slows down
with a uniform acceleration of -5 m/s2. It takes the cheetah 5
seconds to stop. The cheetah travels meters within the 5
seconds. (in meters)

Answer 1

• Initial velocity=u=25m/s
• Acceleration=a=-5m/s^2
• Time=t=5s
• Distance be s

`\\ \bull\tt\dashrightarrow s=ut+(1)/(2)at^2`

`\\ \bull\tt\dashrightarrow s=25(5)+(1)/(2)(-5)(5)^2`

`\\ \bull\tt\dashrightarrow s=125+(1)/(2)(-125)`

`\\ \bull\tt\dashrightarrow s=125-62.5`

`\\ \bull\tt\dashrightarrow s=62.5m`