Answer:
1st term = 7, 2nd term = 18, 3rd term = 39, 10th term = 403
Explanation:
To find the 1st term substitute 1 for n in the equation:
4(1)² + 1 = (4 × 1) + 3 = 4 + 3 = 7
To find the 2nd term substitute 2 for n in the equation:
4(2)² + 3 = (4 × 4) + 3 = 16 + 3 = 18
To find the 3rd term substitute 3 for n in the equation:
4(3)² + 3 = (4 × 9) + 3 = 36 + 3 = 39
To find the 10th term substitute 10 for n in the equation:
4(10)² + 10 = (4 × 100) + 3 = 400 + 3 = 403
Hope this helps!