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| 7 + m | - 4 > 8

A. m > -2 or m < -20

B. m > 7 or m < 0

C. m > 5 or m < -19

D. m > 9 or m < -15

User Rgrebski
by
8.1k points

1 Answer

4 votes

Answer:

m > 5 or m < -19

Explanation:

We are given the Inequality:


\displaystyle \large - 4 > 8

First, add both sides by 4.


\displaystyle \large - 4 + 4 > 8 + 4 \\ \displaystyle \large

Absolute Value Property


\displaystyle \large{ |a| = \sqrt{ {a}^(2) } }

Given a = any expressions and b = any positive numbers, zero or any expressions.


\displaystyle \largea

From the Inequality, change > to equal


\displaystyle \large{ 7 + m = \pm12}

Subtract 7 both sides.


\displaystyle \large{ 7 - 7 + m = \pm12 - 7} \\ \displaystyle \large{ m = \pm12 - 7}

±12-7 can be 12-7 = 5 or -12-7 = -19


\displaystyle \large{ m = 5, - 19}

Refer to the attachment. The region is when the absolute value function is greater than constant function y = 12 or a blue horizontal line.

Since the absolute graph is above constant graph when x > 5 and x <-19.

Therefore,


\displaystyle \large{ m > 5, m < - 19}

| 7 + m | - 4 > 8 A. m > -2 or m < -20 B. m > 7 or m < 0 C. m > 5 or-example-1
User Amuniz
by
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