Answer:
Li2S
Al2O3
KCl
AlBr3
NaF
Step-by-step explanation:
Li is monovalent (+1), S is divalent (-2)
Al has an oxidation state of +3, Oxygen is -2 2*3=+6 and 3*(-2)=-6
Both K abnd Cl are monvalent (K is +1 and Cl is -1)
AlBr3: Al is +3 and each Br is -1
NaF: both elements have a single charge (+1 for Na and -1 for Br)