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An object is dropped from the top of a tall building. The height S of the object after t seconds I’d given by the equation S = -16t^2+324. Find how many seconds pass before the object hits the ground.

User Riyaz
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Answer:

Explanation:

0 = -16t² + 324

16t² = 324

t² = 20.25

t = 4.5 s

User Pushkraj Lanjekar
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