Question

What is the equation of the line with y intercept (0.8)and slope 3/5​

Answer 1

Explanation:

y = mx + b

m is slope

b is y-intercept

y = 3/5 x + 4/5

5y = 3x + 4

3x - 5y + 4 = 0

All three equations written above are correct, they are just in different formats :)

Answer 2

`\mathbb{FINAL\;ANSWER:}`

`\huge\boxed{\sf{y=\displaystyle(3)/(5) x+0.8}}`

`\mathbb{SOLUTION:}`

Hi! Hope you are having a nice day!

`\mathcal{GIVEN:}`

• Slope of the line
• The line's y-intercept

`\mathcal{TO \ FIND:}`

• The equation of the line using the given information

`\mathcal{PROCESS:}`

• Should we write the equation of the line in Slope-Intercept Form or in Point-Slope Form?

`\mathcal{SLOPE-INTERCEPT\;FORM:}`

• y=mx+b
• where m = slope of the line
• where b = y-intercept of the line

Actually, we do have enough information to write the line's equation in Slope-Intercept form OR in Point-Slope Form.

However, let's write the equation in Slope-Intercept Form.

The y-intercept is 0.8, and the slope is
`\sf{\displaystyle(3)/(5) }`.

Equation:

y=mx+b

Plug m:

`\sf{y=\displaystyle(3)/(5) x+b}`

Plug b:

`\sf{y=\displaystyle(3)/(5) x+0.8}`

Hope you could understand everything.

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