Question

Make y the subject of the equation

2A=x(2y+z)​

Answer 1

Hi there!

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I believe your answer is:

`y = (2A-xz)/(2x); x \\eq 0`

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Here’s why:

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`2A = x(2y+z)\\\\\rightarrow x(2y+z)=2A\\\\\rightarrow(x(2y+z)=2A)/(x)\\\\\rightarrow 2y + z = (2A)/(x)\\\\\rightarrow 2y + z - z = (2A)/(x)-z\\\\\rightarrow 2y = (2A)/(x) - z\\\\\rightarrow(2y = (2A)/(x) - z)/(2)\\\\\rightarrow \boxed{y = (2A-xz)/(2x)}`

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Hope this helps you. I apologize if it’s incorrect.

Answer 2

2A = 2xy + xz

2A - xz = 2xy + xz - xz

2A - xz = 2xy

( 2A - xz ) ÷ 2x = 2xy ÷ 2x

A/x - z/2 = y