Question

4x - 2y + 7z² when x = 2, y = 5, and z = 8​

Answer 1

`446`

Explanation:

`4x - 2y + 7z^(2)`

`x = 2`

`y = 5`

`z = 8`

`4\left(2\right)-2\left(5\right)+7\left(8\right)^2`

Multiply 4 and 2 to get 8

`8-2* 4+7*8^(2)`

Multiply 2 and 5 to get 10:-

`8-10+7*8^(2)`

Subtract 10 from 8 to get -2, and then calculate 8 to the power of 2 and get 64:-

`-2+7* 64`

Multiply 7 and 64 get 488:

`-2+448`

Add -2 and 488 to get 446

`446`

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Answer 2

446

Explanation:

x = 2

y = 5

z = 8

4x = 4*2 = 8

-2y = -2*5 = -10

7z^2 = 7 * 8^2 = 7 * 64 = 448

8 - 10 + 448 = 446