Question

a motor has torque of 200 nm if i motors attached to an arm with a length of 25 cm and a string is too attached to the end approximately how many kilograms should i be able to lift

Answer 1

With a torque of 200 N·m and a lever arm of 25 cm, one can lift approximately 81.55 kilograms by converting the torque to force and dividing by the acceleration due to gravity.

Step-by-step explanation:

To calculate how many kilograms you can lift with a torque of 200 N·m applied to an arm with a length of 25 cm, you need to understand the relationship between torque (T), force (F), and lever arm distance (r). Torque is the product of force and the perpendicular distance from the pivot point to the line of action of the force, expressed as T = F × r.

First, we convert the lever arm length to meters: 25 cm = 0.25 m. Then, we rearrange the torque formula to solve for the force: F = T / r = 200 N·m / 0.25 m = 800 N.

Since 1 N = 1 kg·m/s2, we can convert the force into weight (mass under the influence of gravity) by dividing by the acceleration due to gravity (g = 9.81 m/s2): Mass = F / g = 800 N / 9.81 m/s2 ≈ 81.55 kg.

Therefore, with a 200 N·m torque and an arm length of 25 cm, you should be able to lift approximately 81.55 kilograms.