Question

Which is not a form of potential energy?

gravitational
chemical
clastic
thermal

Answer 1

Step-by-step explanation:

`\underline{\underline{\large\bf{Given:-}}}`

`\red{➤}\:`
`\textsf{}`
`\sf Points\:(2, 4), (0,3)\: and\; (k, -4) \:are\; collinear`

`\underline{\underline{\large\bf{To Find:-}}}`

`\orange{☛}\:`
`\textsf{Value of k}`
`\sf`

`\\`

`\underline{\underline{\large\bf{Solution:-}}}\\`

Let us consider these points on a line AC such that point B lies in between points A and C as these lines are collinear -

`\\A(2,4) \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: B(0,3) \: \: \: \: \: \: \: \: \: \: \: \: C(k,4)\\ \bull \frac{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }{} \bull \frac{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }{} \bull \\`

If lines are collinear then,

`\green{ \underline { \boxed{ \sf{AB+BC=AC}}}}`

`\\`

We will find distance between points by distance formula-

`\red{\underline{\boxed{\sf{Distance=√((x_2-x_1)^2+(y_2-y_1)^2)}}}}`

`\\(x_1,y_1) \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: (x_2,y_2)\\ \bull \frac{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }{} \bull \frac{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }{} \bull \\`

`\begin{gathered}\\\\longrightarrow\quad \sf AB = \sqrt{(0 - 2) ^(2) + (3 - 4) ^(2) } \\\end{gathered}`

`\begin{gathered}\\\\longrightarrow\quad \sf √(4 + 1 ) \\\end{gathered}`

`\begin{gathered}\\\\longrightarrow\quad \sf √(5 ) \\\end{gathered}`

`\\`

`\begin{gathered}\\\\longrightarrow\quad \sf BC = \sqrt{(k - 0) ^(2) + (-4-3) ^(2) } \\\end{gathered}`

`\begin{gathered}\\\\longrightarrow\quad \sf √(k^2+49 ) \\\end{gathered}`

`\\`

`\begin{gathered}\\\\longrightarrow\quad \sf AC = \sqrt{(k - 2) ^(2) + (-4 - 4) ^(2) } \\\end{gathered}`

`\begin{gathered}\\\\longrightarrow\quad \sf √(k^2+4-4k+64 ) \\\end{gathered}`

`\\`

`\begin{gathered}\\\\longrightarrow\quad \sf AC = √(k^2-4k+68 ) \\\end{gathered}`

`\purple{ \underline { \boxed{ \sf{AB+BC=AC}}}}`

`\\\underline{\tt\pink{Putting \:Values-}}\\`

`\begin{gathered}\\\quad\longrightarrow\quad \sf √(5 )+√(k^2+49 ) = √(k^2-4k+68 )[ \\\end{gathered}`

Squaring Both Sides-

`\begin{gathered}\\\quad\longrightarrow\quad \sf (√(5 )+√(k^2+49 ) )^2= (√(k^2-4k+68))^2 \\\end{gathered}`

Answer 2

Clastic is not a form of potential energy