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Please help!!!!
Trigonometry
Find the value of aBc
Compound shape

Please help!!!! Trigonometry Find the value of aBc Compound shape-example-1
User Tacha
by
8.2k points

1 Answer

4 votes

Answer:

∠ ABC = 75°

Explanation:

using the sine ratio in right Δ ABD

sin ABD =
(opposite)/(hypotenuse) =
(AD)/(AB) =
(4)/(8) =
(1)/(2) , then

∠ ABD =
sin^(-1) (
(1)/(2) ) = 30°

Using the sine ratio in right Δ CBD

sin CBD =
(opposite)/(hypotenuse) =
(CD)/(BC) =
(3)/(3√(2) ) =
(1)/(√(2) ) , then

∠ CBD =
sin^(-1) (
(1)/(√(2) ) ) = 45°

Then

∠ ABC = ∠ABD + ∠ CBD = 30° + 45° = 75°

User Kiko Seijo
by
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