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5(h+7);5h+35

answer please​

User Mlodhi
by
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1 Answer

5 votes

Answer:
5\left(h+7\right)

Step-by-step explanation:
\mathrm{Find\:Least\:Common\:Multiplier\:of\:}5\left(h+7\right),\:5h+35


5\cdot \left(h+7\right)

User Enumy
by
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