63.0k views
14 votes
Find all real solutions Tan pi/3 x-3=0

User Leydy
by
8.0k points

1 Answer

5 votes

Explanation:

If the question is like this,


\tan( (\pi)/(3)x - 3 ) = 0

We take the arc tan of both sides.


\tan( - 1) ( \tan( (\pi)/(3)x - 3 ) = \tan {}^( - 1) ( {}^( )0 )


(\pi)/(3) x - 3 = 0


(\pi)/(3) x = 3


= (9)/(\pi)

Since the period of a tan function, is pi, we divide pi by pi/3 since pi/3is the coeffeicent of the x variable


(\pi)/( (\pi)/(3) ) = 3

So the answer is


(9)/(\pi) + 3n

If this the question,


\tan( (\pi)/(3) x) = 3


(\pi)/(3) x = 1.249


x = (3.747)/(\pi)

The period is once again 3 so we have


(3.747)/(\pi) + 3n

where n is a interger.

User Ivan Poliakov
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories