1 Answer

Ivan Poliakov · Answer 1 · 2023-12-01T20:09:01+0000

Explanation:

If the question is like this,

$\tan( (\pi)/(3)x - 3 ) = 0$

We take the arc tan of both sides.

$\tan( - 1) ( \tan( (\pi)/(3)x - 3 ) = \tan {}^( - 1) ( {}^( )0 )$

$(\pi)/(3) x - 3 = 0$

$(\pi)/(3) x = 3$

$= (9)/(\pi)$

Since the period of a tan function, is pi, we divide pi by pi/3 since pi/3is the coeffeicent of the x variable

$(\pi)/( (\pi)/(3) ) = 3$

So the answer is

$(9)/(\pi) + 3n$

If this the question,

$\tan( (\pi)/(3) x) = 3$

$(\pi)/(3) x = 1.249$

$x = (3.747)/(\pi)$

The period is once again 3 so we have

$(3.747)/(\pi) + 3n$

where n is a interger.

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