Question

F(x)=\sqrt(32x) g(x)=\sqrt(2x) find (f x g)(x) assume x >=0

Answer 1

(f * g)(x) = 8x, when x >=0

Explanation:

I. Given f(x) = sqrt32x, g(x) = sqrt(2x)

Find (f*g) =
`√(32) * √(x) * √(2) *√(x)` {when
`√(32x) = √(32) *√(x)`

=
`√(32 * 2) * √(x * x)`

=
`√(64) * x`

(f * g) = 8x

So (f * g)(x) = 8x, when x >=0

But if your question is fog, the answer will be different.

Hope that help :)