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A bag contains 5 red counters, 3 blue counters and 1 yellow counter. What is the probability that a randomly chosen counter from the bag will not be blue? Give your answer as a fraction in its simplest
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A bag contains 5 red counters, 3 blue counters and 1 yellow counter. What is

the probability that a randomly chosen counter from the bag will not be blue?
Give your answer as a fraction in its simplest form.

User FreeClimb
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8.5k points

1 Answer

4 votes
Answer: 2/3

First, you have to add all of the counters to get the denominator (bottom number). 5+3+1=9. The number of blue counters is 5+1 (red+yellow)=6. Then use the fraction 6/9. Then, simplify to get 2/3.
User MichaelTiefenbacher
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