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The position of a particle s given by x=3-2t+3t^2. What is its instantaneous velocity and instantaneous acceleration as t=3.

At what time is the particle at rest

User Sauumum
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1 Answer

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Step-by-step explanation:

velocity = dx/dt


(dx)/(dt) = 6t - 2 = 16

acceleration =


\frac{ {d}^(2)x }{d {t}^(2) } = 6 \ \\

User Hikarikuen
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