Question

Solve the formula for x.
S=2πzx+7πz2

Answer 1

`\\ \tt\longmapsto S=2\pi zx+7\pi z^2`

`\\ \tt\longmapsto S=\pi z(2x+7z)`

`\\ \tt\longmapsto 2x+7z=(S)/(\pi z)`

`\\ \tt\longmapsto 2x=(S)/(\pi z)-7z`

`\\ \tt\longmapsto 2x=(S-7\pi z^2)/(\pi z)`

`\\ \tt\longmapsto x=(S-7\pi z^2)/(2\pi z)`

`\\ \tt\longmapsto x=\pi z\left((S-7z)/(2)\right)`

Answer 2

Given:

• S = 2πzx + 7πz²

Isolate x:

• 2πzx = S - 7πz²

Divide both sides by 2πz:

• x = (S - 7πz²)/(2πz)

• x = S/(2πz) - 3.5z