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A particle R moves with a velocity of 6 m/s due East and

another particle S moves at 8 m/s due South. What is the
magnitude of the velocity of Rw.r.t S?
a 10 m/s
b 14 m/s
C2s
d 7 m/s

1 Answer

3 votes

Answer:

10 m/s

Step-by-step explanation:

C^2=8^2 + 6^2= 64 + 36=100

C=square root 100 = 10m/s

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