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NO LINKS!!! Please help me with this problem. Part 2​

NO LINKS!!! Please help me with this problem. Part 2​-example-1

2 Answers

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  • ∆H=11200-9000=2200ft

  • Angle of inclination=17°

We need Hypotenuse


\\ \rm\rightarrowtail sin\theta=(Perpendicular)/(Hypotenuse)

  • Hypotenuse be h


\\ \rm\rightarrowtail sin17=dfrac{2200}{h}


\\ \rm\rightarrowtail h=2200/sin17


\\ \rm\rightarrowtail h=2200/0.2923


\\ \rm\rightarrowtail h=7526.51ft

NO LINKS!!! Please help me with this problem. Part 2​-example-1
User TechyGypo
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7.8k points
11 votes

Answer: approximately 7525 feet

A more accurate value is 7,524.6679636332 feet, but even that isn't fully exact.

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Step-by-step explanation:

The change in height, or delta height value, is 11200-9000 = 2200 which is the vertical component of the right triangle shown below. This side is opposite the reference angle, aka the angle of elevation 17°

The hypotenuse is x, which is the length of the trail. Assume we're dealing with a flat and straight surface. Of course realistically the ground is very likely going to be bumpy with various curved complexities; but we'll simplify things greatly.

We'll use the sine ratio to find x.

sin(angle) = opposite/hypotenuse

sin(17) = 2200/x

x*sin(17) = 2200

x = 2200/sin(17)

x = 7,524.6679636332

Assuming your teacher wants you to round to the nearest whole number, then we'd get to 7525 feet

NO LINKS!!! Please help me with this problem. Part 2​-example-1
User Maksym Demidas
by
8.7k points

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