Answer:
B, E, F
Explanation:
If the system has infinite solutions, then the 2 equations will be identical.
So we are looking for an equation, which, when simplified or rearranged or multiplied by a constant, will be the same as the given equation
If we multiply equation A by 2 we get: 4x + 6y = 12
This is not the same as the original equation since the operation sign is addition rather than subtraction.
If we divide equation B by 5 we get: 4x - 6y = 12
This is identical to the original equation, and therefore could be the second equation.
Equation C: y = (2/3)x + 12
Multiply by 3: 3y = 2x + 36
Multiply by 2: 6y = 4x + 72
Rearrange: 4x - 6y = -72
If we divide equation D by 1.5 we get: 4x - (8/3)y = 8
Equation E: y = (2/3)x - 2
Multiply by 3: 3y = 2x - 6
Multiply by 2: 6y = 4x - 12
Rearrange: 4x - 6y = 12
This is identical to the original equation, and therefore could be the second equation.
Equation F: 3y = 2x - 6
Multiply by 2: 6y = 4x - 12
Rearrange: 4x - 6y = 12
This is identical to the original equation, and therefore could be the second equation.