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5 votes
Solve the equation by factoring:
X^3 - 9x^2 + 18x = 0

User Foxygen
by
8.3k points

2 Answers

3 votes

Answer:

x=0,3,6

Explanation:

x³-9x²+18x=0

x(x²-9x+18)=0

x[x²-3x-6x+18]=0

x[x(x-3)-6(x-3)]=0

x(x-3)(x-6)=0

x=0,3,6

User Narthring
by
8.1k points
4 votes


\large \mathfrak{Solution : }

Let's factorise :


  • x( {x}^(2) - 9x + 18) = 0


  • x( {x}^(2) - 6x - 3x + 18) = 0


  • x( x(x - 6) - 3(x - 6)) = 0


  • x(x - 6)(x - 3) = 0

now there are three cases :

1. when, x - 6 = 0

  • x = 6

2. when x - 3 = 0

  • x = 3

3. when x = 0

  • x = 0

i hope it helped...

User Tim Diels
by
8.6k points

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