Question

Solve the equation by factoring:
X^3 - 9x^2 + 18x = 0

Answer 1

x=0,3,6

Explanation:

x³-9x²+18x=0

x(x²-9x+18)=0

x[x²-3x-6x+18]=0

x[x(x-3)-6(x-3)]=0

x(x-3)(x-6)=0

x=0,3,6

Answer 2

`\large \mathfrak{Solution : }`

Let's factorise :

• 
  `x( {x}^(2) - 9x + 18) = 0`

• 
  `x( {x}^(2) - 6x - 3x + 18) = 0`

• 
  `x( x(x - 6) - 3(x - 6)) = 0`

• 
  `x(x - 6)(x - 3) = 0`

now there are three cases :

1. when, x - 6 = 0

• x = 6

2. when x - 3 = 0

• x = 3

3. when x = 0

• x = 0

i hope it helped...