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What is the pH if H+ = 4.0 times 10 to the power of negative 8
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What is the pH if H+ = 4.0 times 10 to the power of negative 8

User Yehosef
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Answer:


pH = - log[H {}^( + ) ] \\ pH = - log(4.0 * {10}^( - 8) ) \\ { \boxed{ \boxed{pH = 7.4}}}

User Insilico
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