Question

Help pls and thanks!!!

Answer 1

y = - 3x - 8

Explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y =
`(1)/(3)` x + 2 ← is in slope- intercept form

with slope m =
`(1)/(3)`

Given a line with slope m then the slope of a line perpendicular to it is

`m_(perpendicular)` = -
`(1)/(m)` = -
`(1)/((1)/(3) )` = - 3 , then

y = - 3x + c ← is the partial equation

To find c substitute (- 3, 1 ) into the partial equation

1 = 9 + c ⇒ c = 1 - 9 = - 8

y = - 3x - 8 ← equation of perpendicular line

Answer 2

y = -3x - 8

Explanation:

`y =(1)/(3)x+ 2`

Here slope m = (1/3)

Slope of the perpendicular line =
`(-1)/(m)` = -1 ÷
`(1)/(3) = -1 *(3)/(1)= - 3`

Slope m1 = -3 and (-3 ,1)

Equation of line:

y -y1 = m(x -x1)

y - 1 = -3(x - [-3])

y - 1 = -3(x + 3)

y - 1 = (-3) *x + 3*(-3)

y - 1 = -3x - 9

y = -3x -9 +1

y = -3x - 8