Question

Determine the sum of the first 10 terms of each geometric series.
a) 4 + 12 + 36 + ...

Answer 1

I think the sum of the first 10terms of each geometric series is

4x3=12

= 4+12

12x3=36

=4+12+36

36x3=108

=4+12+36+108

108x3=324

=4+12+36+108+324

324x3=972

=4+12+36+108+324+972

972x3=2916

= 4+12+36+108+324+972+2916

2916x3=8748

=4+12+36+108+324+972+2916+8748

8748x3=26244

=4+12+36+108+324+972+2916+8748+26244

26244x3=78732

=4+12+36+108+324+972+2916+8748+26244+78732=the sum of the geometric series which is = 118,096.

hope this helps I am not sure of the answer but I tried my best.