Question

The rhumbas has a perimeter or 16 and height of 3 what is the area ?

Answer 1

`A=(3√(55))/(2)`

Explanation:

For a height h, a perimeter P, and an area A, use the following formula:

`A=(1)/(4)h\sqrt{P^(2)-4h^(2) }`

Next, replace the variables with the given values:

`A=(1)/(4)(3)\sqrt{(16)^(2)-4(3)^(2) }`

Solve the inside of the square root:

`A=(1)/(4)(3)√(256-36)\\A=(1)/(4)(3)√(220)`

Multiply outside of the square root:

`A=(3)/(4)√(220)\\`

Simplify the square root:

`A=((3)/(4))2√(55)\\`

Multiply outside of the square root once more:

`A=(3)/(2)√(55)\\`

Simplify:

`A=(3√(55))/(2)`, or ≈ 11.12429773

Answer 2

I think the answer is 15 cuz if the height is 3; 3 on each side is 6 so 6-16=10 and 10 divided by 2 for the two others sides is 5… and 5x3=15