Question

B is on line AC. If AC = 28, AB = x^2+2x, and BC = x, Find the value of x and AB

Answer 1

X=10. Is the awnser for this one

Answer 2

X = 4

Explanation:

AB + BC = AC

x^2 +2x + x = 28

×^2 + 3× - 28 = 0

Step 1: Factor left side of equation.

(x−4)(x+7)=0

Step 2: Set factors equal to 0.

x−4=0 or x+7=0

x=4 or x=−7

x = 4 is the correct answer because the distance cant be negative