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Using your answers from Questions 21 and 22, about how much further is it to drive than to walk directly from building A to Building B? Round to the nearest whole number. Question 21 = 433, and Question 22 = 250

A: 366 m

B: 683 m

C: 183 m

D: 250 m

Using your answers from Questions 21 and 22, about how much further is it to drive-example-1
User Amertkara
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2 Answers

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  • We need a


\\ \rm\Rrightarrow cos60=(a)/(500)


\\ \rm\Rrightarrow a=500(cos60)


\\ \rm\Rrightarrow a=500(1/2)


\\ \rm\Rrightarrow a=250m

User Davidhtien
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1 vote

Question↷

Building A and building B are 500 meters apart. There is no road between them, so to drive from building A to building B, it is necessary to first drive to building C and then to building B. About how much farther is it to drive than to walk directly from building A to building B? Round to

the nearest whole number.

Answer ↷

183 meters

Solution ↷

we know that,

In a right angled triangle


⇒cos \: 60° \: = (adjacent \: side)/(hypotenuse) \\


⇒cos \: 60° \: = (BC)/(AB) \\


⇒ (1)/(2) \: = (a)/(500) \\


⇒a = 250

Also, we know that,


⇒sin \: 60° \: = (opposite \: side)/(hypotenuse) \\


⇒ ( √(3) )/(2) \: = (AC)/(AB) \\


⇒ ( √(3) )/(2) \: = (b \:)/(500) \\


⇒b = 250 √(3) = 433(approx)

Now,

Distance covered to walk directly from building A to buliding B ↷


⇒AC+BC-AB


⇒433 + 250 - 500


⇒683 - 500


⇒183m

Hence , 183m distance will be require to walk directly from building A to buliding B

User Evgenii Gostiukhin
by
8.1k points

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