Question

Using your answers from Questions 21 and 22, about how much further is it to drive than to walk directly from building A to Building B? Round to the nearest whole number. Question 21 = 433, and Question 22 = 250

A: 366 m

B: 683 m

C: 183 m

D: 250 m

Answer 1

• We need a

`\\ \rm\Rrightarrow cos60=(a)/(500)`

`\\ \rm\Rrightarrow a=500(cos60)`

`\\ \rm\Rrightarrow a=500(1/2)`

`\\ \rm\Rrightarrow a=250m`

Answer 2

Question↷

Building A and building B are 500 meters apart. There is no road between them, so to drive from building A to building B, it is necessary to first drive to building C and then to building B. About how much farther is it to drive than to walk directly from building A to building B? Round to

the nearest whole number.

Answer ↷

183 meters

Solution ↷

we know that,

In a right angled triangle

`⇒cos \: 60° \: = (adjacent \: side)/(hypotenuse) \\`

`⇒cos \: 60° \: = (BC)/(AB) \\`

`⇒ (1)/(2) \: = (a)/(500) \\`

`⇒a = 250`

Also, we know that,

`⇒sin \: 60° \: = (opposite \: side)/(hypotenuse) \\`

`⇒ ( √(3) )/(2) \: = (AC)/(AB) \\`

`⇒ ( √(3) )/(2) \: = (b \:)/(500) \\`

`⇒b = 250 √(3) = 433(approx)`

Now,

Distance covered to walk directly from building A to buliding B ↷

`⇒AC+BC-AB`

`⇒433 + 250 - 500`

`⇒683 - 500`

`⇒183m`

Hence , 183m distance will be require to walk directly from building A to buliding B