62.0k views
1 vote
DF= 78, DE = 5x -9, EF = 2x + 10, find DE.

2 Answers

3 votes

DF = 78, DE = 5x - 9, EF = 2x + 10, find DE.

Solve for x first.

5x - 9 + 2x + 10 = 78

7x + 1 = 78

7x = 78 - 1

7x = 77/7

x = 11

Then substitute the value of x to find DE.

DE = 5x - 9

5(11) - 9

55 - 9

DE = 46

Therefore, the value of DE is 46

User Johannes Thoma
by
8.6k points
2 votes

Question:

DF= 78, DE = 5x -9, EF = 2x + 10, find DE.

Solution:

First, solve for the value of x.

  • DE + EF = DF
  • (5x - 9) + (2x + 10) = 78
  • 7x + 1 = 78
  • 7x = 78 - 1
  • 7x = 77/7
  • x = 11

Then, plug and substitute the value of x to find the DE.

  • DE
  • 5x - 9
  • 5(11) - 9
  • 55 - 9
  • 46

Answer:

  • The value of DE is 46
User Rob MacEachern
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.