Question

Someone please help me answer this ASAP<3

Answer 1

C

Explanation:

To solve an equation of the form
`ax^2+bx+c=0`

Use completing the square formula:

`a\left(x+(b)/(2a) \right)^2+c-(b^2)/(4a)=0`

Given equation:

`2x^2+16x-8=0`

Therefore,

• a = 2
• b = 16
• c = -8

Substitute these values into the formula:

`2\left(x+(16)/(2(2)) \right)^2+(-8)-(16^2)/(4(2))=0`

`2\left(x+4} \right)^2-40=0`

To solve, add 40 to both sides:

`2(x+4)^2=40`

Divide both sides by 2:

`(x+4)^2=20`

Square root both sides:

`x+4=\pm √(20)`

`x+4=\pm √(4 \cdot 5)`

`x+4=\pm 2√(5)`

subtract 4 from both sides:

`x=-4\pm 2√(5)`