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How many moles of Al2O3 are contained in 45.1 g of Al2O3?
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4 votes
How many moles of Al2O3 are contained in 45.1 g of Al2O3?

User Srisudhir T
by
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1 Answer

3 votes

Answer:

0.44mol

Step-by-step explanation:

1mol/102g=xmol/45.1g

-> x=(45.1x1)/102

x=0.44mol

User Glennr
by
4.7k points
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