Question

6(5r-3)= what does it equal

Answer 1

`\boxed{\tt 30r-18}`

Explanation:

`\tt 6(5r-3)`

1) Expand by distributing terms.

`\tt 6* 5r+6* -3`

`\tt 6* 5r=\boxed{\tt 30r}`

`\tt 30r+6* -3`

`\tt 6* -3=\boxed{\tt -18}`

`\tt 30r-18`

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Answer 2

`\tex\text{This expression uses the \underline{distributive property.} }`

`\tex\text{To solve a distributive property, multiply the outside term with the inside terms.}`

Step-by step calculations:

`\rightarrow 6(5r - 3)`

Multiplying the outside term with the inside terms:

`\rightarrow (6 * 5r) + (6 * -3)`

`\rightarrow (30r) + (-18)`

Opening the parenthesis:

`\rightarrow \boxed{\bold{30r - 18}}`