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Find the distance between the two points rounding to the nearest tenth (4,0) and (0,9)

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Answer:


\boxed {\boxed {\sf 9.8}}

Explanation:

We are asked to find the distance between two points. We will calculate the distance using the following formula;


d= \sqrt {(x_2-x_1)^2+(y_2-y_1)^2

In this formula, (x₁ , y₁) and (x₂ , y₂) are the 2 points. We are given the points (4,0) and (0,9). If we match the value and the corresponding variable, we see that:

  • x₁= 4
  • y₁= 0
  • x₂= 0
  • y₂= 9

Substitute the values into the formula.


{d= \sqrt {(0-4)^2+(9-0)^2

Solve inside the parentheses.

  • (0-4)= -4
  • (9-0)= 9


d=\sqrt{(-4)^2+ (9)^2

Solve the exponents. Remember that squaring a number is the same as multiplying it by itself.

  • (-4)²= -4*-4= 16
  • (9)²= 9*9= 81


d= \sqrt{(16)+(81)

Add.


d= \sqrt{97

Take the square root of the number.


d=9.848857802

Round to the nearest tenth. The 4 in the hundredth place tells us to leave the 8 in the tenth place.


d\approx 9.8

The distance between the two points (4,0) and (0,9) is approximately 9.8

User Crasholino
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