Question

The sum of 4 consecutive integers is 406. find the integers

Answer 1

Explanation:

let the numbers be n,n+1,n+2,n+3

n+n+1+n+2+n+3=406

4n+6=406

4n=406-6=400

n=400/4=100

then the numbers are

100,100+1,100+2,100+3

or

100,101,102,103

Answer 2

Answer and Step-by-step explanation:

When trying to figure this out, we know that the numbers have to be one after the other, like 1, 2, 3, 4, or 55. 56, 57, 58. The last digit in the numbers also have to add to 6.

The answer is:

100 + 101 + 102 + 103

It adds up to 406, and the integers are consecutive.

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I hope this helps!