Final answer:
When Bradd and Pitt meet, they are approximately 176 meters west of the flagpole, which is the result of calculating the distance Bradd covers in 0.6471 hours at a speed of 9km/h towards the east.
Step-by-step explanation:
To determine the displacement from the flagpole where Bradd and Pitt meet, we can set up an equation based on their rates and the initial distances from the flagpole.
Let's denote the time at which they meet as t hours. In t hours, Bradd would cover a distance of 9km/h × t, and Pitt would cover a distance of 8km/h × t. Since Bradd is initially 6km west of the flagpole and Pitt is 5km east, we are interested in the point where the sum of the distances they run equals 11km (6km + 5km).
Therefore, we have the equation:
9t (Bradd's distance) + 8t (Pitt's distance) = 11km (total distance)
By solving the equation for t, we find that the runners meet after:
t = 11km / (9km/h + 8km/h)
t = 11km / 17km/h
t = 0.6471 hours
At this time, Bradd would have run:
Distance run by Bradd = 9km/h × 0.6471h ≈ 5.824 km
Therefore, Bradd is around 0.176 km or 176 meters from the flagpole when they meet, since he started 6 km away and has covered approximately 5.824 km towards it.
Pitt is in the opposite direction, so we do not need to calculate his precise distance from the flagpole as the question only asks for the displacement where they meet relative to the flagpole.