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A rectangle has a length of x and a width of 6x^3 + 3− x^2. Find the perimeter of the rectangle when the length is 5 feet
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A rectangle has a length of x and a width of 6x^3 + 3− x^2. Find the perimeter of the rectangle when the length is 5 feet

User Murilo Vasconcelos
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1 Answer

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Answer:

1466 feet

Explanation:

If length is 5 feet, x=5. The width will be 6*(5)^3+3-(5)^2=728 feet. The perimeter will be 2*(l+b)=2*733=1466 feet

User Sioux
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