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Three resistors 2 k\ohm, 2.5 k\ohm and 3 k\ohm are connected in series. A power supply is connected in the circuit, and applies a voltage of 10.00 V across all three. Calculate the current in the circuit. Enter results in terms of milliamps (mA).

User Jozefow
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1 Answer

6 votes

Answer:

1.33 mA

Step-by-step explanation:

V=IR

I=10/(7.5×10³)

=1.33×10-³A

=1.33mA

User Farhad Navayazdan
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6.7k points