Given the expression:
![\displaystyle \large{ √(50) + √(18) - 8 √(2) }](https://img.qammunity.org/2022/formulas/mathematics/high-school/sbs7f87cbacl7wkl3kbpjfj2qmwr0eqzhu.png)
Since we have 2 in the square root from 8√2. We will be converting terms in √2 form so we can. evaluate.
As we know, 50 comes from 5×10 = 5×5×2
and 18 comes from 9×2 = 3×3×2.
![\displaystyle \large{ √(5 * 5 * 2) + √(3 * 3 * 2) - 8 √(2) }](https://img.qammunity.org/2022/formulas/mathematics/high-school/i49sx6gqhjxjcdgimyxrug3ggr2ntyzqhq.png)
In the square root, if there are two same numbers, we can pull it out as one.
Ex. √5×5 would be 5. Refer to below:
![\displaystyle \large{ √(a * a) = \sqrt{ {a}^(2) } = |a| }](https://img.qammunity.org/2022/formulas/mathematics/high-school/eo78nqwj8poac2opiak4d2ragsofssrwu2.png)
Since there are two fives and two threes in the square root, we pull these numbers out only one.
![\displaystyle \large{ 5√(2) + 3 √(2) - 8 √(2) }](https://img.qammunity.org/2022/formulas/mathematics/high-school/i78wymxe4o6je2illtlbpchztmpjngmdlj.png)
Because these terms have the same square root of 2, we can evaluate 5+3-8.
![\displaystyle \large{ 8 √(2) - 8 √(2) } = 0](https://img.qammunity.org/2022/formulas/mathematics/high-school/65mbkfn3m3z20qr6ghyfoabyw3n9unyhhc.png)
Of course, like term - like term = 0
Hence, the answer is 0.