Question

A

1
-4
-3
-2
-1
0
00
-1
-2.
The distance AB rounded to the
nearest tenth = [?]
Hint: d = V(x2 – x1)2 + (y2 - yı)2

Answer 1

AB ≈ 2.8

Explanation:

Calculate the distance d using the distance formula

d =
`\sqrt{(x_(2)-x_(1))^2+(y_(2)-y_(1))^2 }`

with (x₁, y₁ ) = A (- 3, 1) and (x₂, y₂ ) = B (- 1, - 1)

d =
`√((-1-(-3))^2+(-1-1)^2)`

=
`√((-1+3)^2+(-2)^2)`

=
`√(2^2+4)`

=
`√(4+4)`

=
`√(8)`

≈ 2.8 ( to the nearest tenth )

Answer 2

2.8

Explanation:

use the distance formula in the picture:

`√((-1-(-3))^2+((-1)-1)^2) = √(2^2+(-2)^2) = √(4+4) = √(8) = 2√(2) = 2.8284`