222k views
2 votes
A skydiver slows down from 65 m/s to 5 m/s by opening the parachute. If this

takes 0.75 seconds, what is the skydiver's acceleration?
A. 45 m/s2 up
B. 80 m/s2 up
C. 45 m/s2 down
D. 80 m/s2 down

2 Answers

3 votes

Answer:

D. -80m/s^2

Step-by-step explanation:

V = u + at

5 = 65 + a (0.75)

0.75a = -60

a = -60/0.75

a = -80m/s^2

Therefore, is decelerating at 80m/s^2

User Tiago Fael Matos
by
8.6k points
0 votes

Answer:


\boxed {\boxed {\sf D. \ 80 \ m/s^2 \ down}}

Step-by-step explanation:

We are asked to find the acceleration of a skydiver. Acceleration is the change in velocity over the change in time, so the formula for calculating acceleration is:


a= (v_f-v_i)/(t)

The skydiver was initially traveling 65 meters per second, then he slowed down to a final velocity of 5 meters per second. He slowed down in 0.75 seconds.


\bullet \ v_f = 5 \ m/s \\\bullet \ v_i= 65 \ m/s \\\bullet \ t= 0.75 \ s

Substitute the values into the formula.


a= ( 5 \ m/s - 65 \ m/s)/(0.75 \ s)

Solve the numerator.


a= (-60 \ m/s)/(0.75 \ s)

Divide.


a= -80 \ m/s^2

The acceleration of the skydiver is -80 meters per second squared or 80 meters per second squared down. The skydiver is slowing down or decelerating, so the acceleration is negative or down.

User Wilkin
by
7.3k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.