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. f(x) = Square root of quantity x plus nine. ; g(x) = 8x - 13 Find f(g(x)). (1 point)

f(g(x)) = 2 Square root of quantity two x minus one.
f(g(x)) = 8 Square root of quantity x minus four.
f(g(x)) = 2 Square root of quantity two x plus one.
f(g(x)) = 8 Square root of quantity x plus nine - 13

User Bzu
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2 Answers

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\\ \sf\longmapsto f(x)=√(x+7)


\\ \sf\longmapsto g(x)=8x-11

  • g(x) will be put on the place of x


\\ \sf\longmapsto f(g(x))=√(8x-11+7)


\\ \sf\longmapsto f(g(x))=√(8x-4)


\\ \sf\longmapsto f(g(x))=√(4(2x-1))


\\ \sf\longmapsto f(g(x))=2√(2x-1)

User Harmenx
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4 votes

Answer:

2 sqrt(2x-1)

Explanation:

f(x) = sqrt( x+9)

g(x) = 8x-13

f(g(x))

place the function g(x) in for x in f(x)

f(g(x)) = sqrt(8x-13+9)

Combine like terms

f(g(x)) = sqrt(8x-4)

Factor out 4

f(g(x)) = sqrt(4*(2x-1)

2 sqrt(2x-1)

User Wouter Simons
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