Question

. f(x) = Square root of quantity x plus nine. ; g(x) = 8x - 13 Find f(g(x)). (1 point)

f(g(x)) = 2 Square root of quantity two x minus one.
f(g(x)) = 8 Square root of quantity x minus four.
f(g(x)) = 2 Square root of quantity two x plus one.
f(g(x)) = 8 Square root of quantity x plus nine - 13

Answer 1

`\\ \sf\longmapsto f(x)=√(x+7)`

`\\ \sf\longmapsto g(x)=8x-11`

• g(x) will be put on the place of x

`\\ \sf\longmapsto f(g(x))=√(8x-11+7)`

`\\ \sf\longmapsto f(g(x))=√(8x-4)`

`\\ \sf\longmapsto f(g(x))=√(4(2x-1))`

`\\ \sf\longmapsto f(g(x))=2√(2x-1)`

Answer 2

2 sqrt(2x-1)

Explanation:

f(x) = sqrt( x+9)

g(x) = 8x-13

f(g(x))

place the function g(x) in for x in f(x)

f(g(x)) = sqrt(8x-13+9)

Combine like terms

f(g(x)) = sqrt(8x-4)

Factor out 4

f(g(x)) = sqrt(4*(2x-1)

2 sqrt(2x-1)