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Question is posted below

Question is posted below-example-1
User Chidozie Nnachor
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1 Answer

16 votes
16 votes

Answer:

-120/169

Explanation:


sin(\theta) = \pm\sqrt{1-\cos^2{\theta}}=\pm\sqrt{1-((5)/(13))^2}=\pm\sqrt{1-(25)/(169)}=\pm\sqrt{(144)/(169)}=\pm(12)/(13)

In Quadrant IV, sinθ < 0

so sinθ = -12/13

sin2θ = 2 sinθ cosθ = 2 (5/13) (-12/13) = -120/169

User Craig Jones
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