Question

Express b+1/3b-2 with “b” as the subject

Answer 1

`→a = ((b + 1))/((3b - 2)) \\ a(3b - 2) = (b + 1) \\ 3ab - 2a = b + 1 \\ 3ab - b = 2a + 1 \\ b(3a - 1) =( 2a + 1) \\ \boxed{b = ((2a + 1))/((3a - 1)) }✓`

• b = (2a+1)/(3a-1) is the right answer.

Answer 2

b =
`(1+2a)/(3a-1)`

Explanation:

Given

a =
`(b+1)/(3b-2)` ( multiply both sides by 3b - 2 )

a(3b - 2) = b + 1 ← distribute left side

3ab - 2a = b + 1 ( subtract b from both sides )

3ab - b - 2a = 1 ( add 2a to both sides )

3ab - b = 1 + 2a ← factor out b from each term on the left side

b(3a - 1) = 1 + 2a ( divide both sides by 3a - 1 )

b =
`(1+2a)/(3a-1)`