Differentiate y= ln (6 – 3x)^4

asked Dec 4, 2022 123k views

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Explanation:

$(dy)/(dx) = \frac{1}{ {(6 - 3x)}^(4) } * {4(6 - 3x)}^(3) ( - 3) \\ = \frac{ - 12 {(6 - 3x)}^(3) }{ {(6 - 3x)}^(4) } \\ = - (12)/(6 - 3x)$

I hope I'm correct. I've never learnt differentiation for log and exponents before

Benrudhart answered Dec 9, 2022

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