Question

Differentiate y= ln (6 – 3x)^4​

Answer 1

Explanation:

`(dy)/(dx) = \frac{1}{ {(6 - 3x)}^(4) } * {4(6 - 3x)}^(3) ( - 3) \\ = \frac{ - 12 {(6 - 3x)}^(3) }{ {(6 - 3x)}^(4) } \\ = - (12)/(6 - 3x)`

I hope I'm correct. I've never learnt differentiation for log and exponents before