Differentiate y= ln (6 – 3x)^4

asked Dec 4, 2022 123k views

2 votes

8.0k points

Please log in or register to add a comment.

3 votes

Explanation:

$(dy)/(dx) = \frac{1}{ {(6 - 3x)}^(4) } * {4(6 - 3x)}^(3) ( - 3) \\ = \frac{ - 12 {(6 - 3x)}^(3) }{ {(6 - 3x)}^(4) } \\ = - (12)/(6 - 3x)$

I hope I'm correct. I've never learnt differentiation for log and exponents before

Benrudhart answered Dec 9, 2022

8.3k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.1m answers