70.1k views
0 votes
Find the acceleration of the blocks when the system is released. The coefficient of kinetic friction is 0.4, and the mass of each block is 1 kg. Neglect the mass of the pulleys and cord.

User Csiz
by
4.1k points

1 Answer

2 votes

Answer:

a = 4.9(1 - sinθ - 0.4cosθ)

Step-by-step explanation:

Really not possible without a complete setup.

I will ASSUME that this an Atwood machine with two masses (m) connected by an ideal rope passing over an ideal pulley. One mass hangs freely and the other is on a slope of angle θ to the horizontal with coefficient of friction μ. Gravity is g

F = ma

mg - mgsinθ - μmgcosθ = (m + m)a

mg(1 - sinθ - μcosθ) = 2ma

½g(1 - sinθ - μcosθ) = a

maximum acceleration is about 2.94 m/s² when θ = 0

acceleration will be zero when θ is greater than about 46.4°

User Himanshi Thakur
by
4.0k points