Question

Find the equation of the tangent line at the point (0,1) of the graph of the function f(x) = x^3 - 2x + 1 ?​

Answer 1

9514 1404 393

Answer:

y = -2x +1

Explanation:

The derivative of the function is ...

f'(x) = 3x^2 -2

so the slope at x=0 is f'(0) = -2. In slope-intercept form, the equation of the tangent line is ...

y = -2x +1